an update of various things

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Luc Bijl 2025-10-05 12:47:09 +02:00
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commit 0e188f5a2c
10 changed files with 165 additions and 197 deletions

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@ -12,7 +12,7 @@ so that $\mathbf{\hat e}^i = A^i_j \mathbf{\hat f}^j$.
## Transformation of tensors
Recall from the section of [tensor-formalism]() that a holor depends on the chosen basis, but the corresponding tensor itself does not. This implies that holors transform in a particular way under a change of basis, which is characteristic for tensors.
Recall from the section of [tensor-formalism](tensor-formalism.md) that a holor depends on the chosen basis, but the corresponding tensor itself does not. This implies that holors transform in a particular way under a change of basis, which is characteristic for tensors.
> *Theorem 1*: let $\mathbf{T} \in \mathscr{T}^p_q(V)$ be a tensor with $p=q=1$ without loss of generality and $B = A^{-1}$. Then $\mathbf{T}$ may be decomposed into
>
@ -26,12 +26,20 @@ Recall from the section of [tensor-formalism]() that a holor depends on the chos
> with the holors related by
>
> $$
> \overline T^i_j = B^i_k A^j_l T^k_l.
> \overline T^i_j = B^i_k A^l_j T^k_l.
> $$
??? note "*Proof*:"
Will be added later.
We have
$$
\begin{align*}
\mathbf{T} &= T^i_j B^k_i \mathbf{f}_k \otimes A^j_l \mathbf{\hat f}^l,\\
&= B^k_i A^j_l T^i_j \mathbf{f}_k \otimes \mathbf{\hat f}^l,\\
&= \overline T^i_j \mathbf{f}_i \otimes \mathbf{\hat f}^j.
\end{align*}
$$
The homogeneous nature of the tensor transformation implies that a holor equation of the form $T^i_j = 0$ holds relative to any basis if it holds relative to a particular one.
@ -54,7 +62,17 @@ The homogeneous nature of the tensor transformation implies that a holor equatio
??? note "*Proof*:"
Will be added later.
We have
$$
\begin{align*}
\bm{\mu} &= \mu_{i_1\dots i_n} A^{i_1}_{j_1} \mathbf{\hat f}^{j_1} \otimes \dots \otimes A^{i_n}_{j_n} \mathbf{\hat f}^{j_n},\\
&= A^{i_1}_{j_1} \cdots A^{i_n}_{j_n} \mu_{i_1\dots i_n} \mathbf{\hat f}^{j_1} \otimes \dots \otimes \mathbf{\hat f}^{j_n},\\
&= A^{i_1}_{j_1} \cdots A^{i_n}_{j_n} [i_1,\dots,i_n] \mathbf{\hat f}^{j_1} \otimes \dots \otimes \mathbf{\hat f}^{j_n},\\
&= \det(A) [j_1,\dots,j_n] \mathbf{\hat f}^{j_1} \otimes \dots \otimes \mathbf{\hat f}^{j_n},\\
&= \overline \mu_{i_1 \dots i_n} \mathbf{\hat f}^{i_1} \otimes \dots \otimes \mathbf{\hat f}^{i_1}.
\end{align*}
$$
Then $\det(A)$ is the volume scaling factor of the transformation with $A$. So that if $\bm{\mu}(\mathbf{e}_1, \dots, \mathbf{e}_n) = 1$, then $\bm{\mu}(\mathbf{f}_1, \dots, \mathbf{f}_n) = \det(A).$
@ -75,10 +93,6 @@ Then $\det(A)$ is the volume scaling factor of the transformation with $A$. So t
>
> then $\mu_{i_1 \dots i_n} = \overline \mu_{i_1 \dots i_n} = [i_1, \dots, i_n]$ is an invariant holor.
??? note "*Proof*:"
Will be added later.
## Transformation of Levi-Civita form
> *Theorem 3*: let $\bm{\epsilon} \in \bigwedge_n(V)$ be the Levi-Civita tensor with
@ -94,4 +108,4 @@ Then $\det(A)$ is the volume scaling factor of the transformation with $A$. So t
??? note "*Proof*:"
Will be added later.
Follows directly from the definition $\bm{\epsilon} = \sqrt{g} \bm{\mu}$.